题目内容：
设函数y＝ax³＋bx²＋cx＋2在x＝0处取得极值，且其图形上有拐点(－1，4)，求常数a，b，c的值．参考答案：
答案解析：
简答题：设函数y＝ax³＋bx²＋cx＋2在x＝0处取得极值，且其图形上有拐点(－1，4)，求常数a，b，c的值．
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- 题目类型：简答题
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