选择题:设函数 f(x) =|x+1|, g(x) =|2x﹣ 1|.(1) 解关于 x 的不等式 f(x) ﹣ g(x) >1;(2) 若 2f(x) +g(x) > 题目分类:高考 题目类型:选择题 查看权限:VIP 题目内容: 设函数 f(x) =|x+1|, g(x) =|2x﹣ 1|.(1) 解关于 x 的不等式 f(x) ﹣ g(x) >1;(2) 若 2f(x) +g(x) >ax+2, 求实数 a 的取值范围.
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