单选题：两列相干平面简谐波振幅都是4Cm，两波源相距30Cm，相位差为π，在波源连线的中垂线上任意一点P，两列波叠加后的合振幅为

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题目内容：
两列相干平面简谐波振幅都是4Cm，两波源相距30Cm，相位差为π，在波源连线的中垂线上任意一点P，两列波叠加后的合振幅为（　　）Cm。 A．8
B．16
C．30
D．0

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答案解析：

一平面简谐波沿x轴正向传播，振幅为A=0.02m，周期T=0.5s，波长λ=100m，原点处质元初相位φ=0，则波动方程

一平面简谐波沿x轴正向传播，振幅为A=0.02m，周期T=0.5s，波长λ=100m，原点处质元初相位φ=0，则波动方程的表达式（　　）。

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