题目内容:
微分方程cosydx+(1+e-x)sinydy=0满足初始条件y x=0=的特解是:
A.cosy=(1+ex)
B.cosy=(1+ex)
C.cosy=4(1+ex)
D.cos2y=(1+ex)
参考答案:
答案解析:
微分方程cosydx+(1+e-x)sinydy=0满足初始条件y x=0=的特解是:
A.cosy=(1+ex)
B.cosy=(1+ex)
C.cosy=4(1+ex)
D.cos2y=(1+ex)