题目内容：
已知椭圆M：x2/a2+y2/b2=1(a>b>0)双曲线N：x2/m2-y2/n2=1,若双曲线N的两条斩近线与椭圆M的四个交点及椭圆M的两个焦点恰为--个正六边形的顶点则椭圆M的焦距与长轴长的比值为____
参考答案：
答案解析：
选择题：已知椭圆M：x2/a2+y2/b2=1(a>b>0)双曲线N：x2/m2-y2/n2=1,若双曲线N的两条斩近线与椭圆M的四个交点及椭圆M的两个焦点恰为--个正
- 题目分类：高考
- 题目类型：选择题
- 查看权限：VIP
下列关于流动镶嵌模型的叙述， 正确的是（ ）
下列关于流动镶嵌模型的叙述， 正确的是（ ）
设集合U={2,3,2a+1}，集合A={3,a}，若C∪A={2}，则实数a=____
设集合U={2,3,2a+1}，集合A={3,a}，若C∪A={2}，则实数a=____
- Shall we play it one more time ? --Im afraid not. I be off for my papers.
- Shall we play it one more time ? --Im afraid not. I be off for my papers.
-Wow!_clean air we have today! -Yes. Look! A lot of adults are doing Kung fu ov
-Wow!_clean air we have today! -Yes. Look! A lot of adults are doing Kung fu over there.
Lee is new in NanchangMaybe he needs a for sightseeing
Lee is new in NanchangMaybe he needs a for sightseeing