题目内容:
已知在25℃,101 kPa下,l g C8H18(辛烷)燃烧生成二氧化碳和液态水时放出48.40 kJ热量,表示上述热化学方程式正确的是( )。 A.C8H18(1)+12.5O2(g)=8CO2(g)+9H2O(g)△H=-48.40 kJ·mol-1
A.C8H18(1)+12.5O2(g)=8CO2(g)+9H2O(g)△H=-48.40 kJ·mol-1
B.C8H18(1)+12.5O2(g)=8CO2(g)+9H2O(1)△H=-5517.6 kJ·mol-1
B.C8H18(1)+12.5O2(g)=8CO2(g)+9H2O(1)△H=-5517.6 kJ·mol-1
C.C8H18(1)+12.5O2(g)=8CO2(g)+9H2O(1)△H=+5517.6 kJ·mol-1
C.C8H18(1)+12.5O2(g)=8CO2(g)+9H2O(1)△H=+5517.6 kJ·mol-1
D.C8H18(1)+12.5O2(g)=8CO2(g)+9H2O(1)△H=-48.40 kJ·mol-1
D.C8H18(1)+12.5O2(g)=8CO2(g)+9H2O(1)△H=-48.40 kJ·mol-1
参考答案:
答案解析: