题目内容:
一振幅为A、周期为T、波长为λ平面简谐波沿x负向传播,在x=λ/2处,t=T/4时振动相位为π,则此平面简谐波的波动方程为:
A.y = Acos(2πt/T-2πx/λ-π/2)
B.y = Acos(2πt/T+2πx/λ+π/2)
C.y = Acos(2πt/T+2πx/λ-π/2)
D.y = Acos(2πt/T-2πx/λ+π/2)
参考答案:
答案解析:
一振幅为A、周期为T、波长为λ平面简谐波沿x负向传播,在x=λ/2处,t=T/4时振动相位为π,则此平面简谐波的波动方程为:
A.y = Acos(2πt/T-2πx/λ-π/2)
B.y = Acos(2πt/T+2πx/λ+π/2)
C.y = Acos(2πt/T+2πx/λ-π/2)
D.y = Acos(2πt/T-2πx/λ+π/2)