题目内容:
某三相电路中,三个线电流分别为
iA=18sin(314t +23)°(A)
iB=18sin(314t-97o)(A)
iC=18sin(314t +143°)(A)
当t=10s时,三个电流之和为:
A.见图A
B.见图B
C.见图C
D.见图D
参考答案:
答案解析:
某三相电路中,三个线电流分别为
iA=18sin(314t +23)°(A)
iB=18sin(314t-97o)(A)
iC=18sin(314t +143°)(A)
当t=10s时,三个电流之和为:
A.见图A
B.见图B
C.见图C
D.见图D