单选题：一横波沿绳子传播时的波动方程为y=0.05Cos(4πχ-10πt)(SI)，则（　　）。

题目内容：

一横波沿绳子传播时的波动方程为y=0.05Cos(4πχ-10πt)(SI)，则（　　）。 A．波长为0.5m
B．波长为0.05m
C．波速为25m/s
D．波速为5m/s

参考答案：

答案解析：

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